M Maynard

asked on January 19, 2025

Atwood machine problem setup

How to set up and solve Atwood machine problems?

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Expert Answer

Answered on April 22, 2025 by EXPERT TUTOR

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Dear M Maynard,

To set up and solve Atwood machine problems, you treat the two hanging masses as a single system connected by an inextensible string over a massless pulley, then apply Newton’s second law to each mass separately. According to expert tutors at My Physics Buddy, the key is choosing a consistent positive direction before writing your equations.

Understanding and Solving Atwood Machine Problems in AP Physics

An Atwood machine is one of those beautifully simple setups that teaches deep ideas about Newton’s laws, tension, and connected systems. It consists of two masses, m1 and m2, hanging on either side of a pulley via a light, inextensible string. The pulley is assumed massless and frictionless in most AP Physics problems. Think of it like a tug-of-war where both teams are pulling on the same rope — the heavier side wins, but the rope constrains both teams to move together.

Step 1 — Identify the System and Choose a Positive Direction

This is where most students go wrong. Before writing a single equation, decide which direction you call positive. The most intuitive choice: define positive as the direction of expected motion. If m2 is heavier, it will accelerate downward, so call downward on the m2 side positive, and upward on the m1 side positive. This means both masses share the same magnitude of acceleration a, since the string length is constant — a constraint called the kinematic constraint.

Step 2 — Draw Free Body Diagrams for Each Mass

For each mass, two forces act: gravity (weight = mg, downward) and string tension T (upward). The tension is the same throughout the string for a massless, frictionless pulley.

For m1 (lighter, accelerating upward — positive direction is upward for this mass):

T − m1g = m1a

For m2 (heavier, accelerating downward — positive direction is downward for this mass):

m2g − T = m2a

Here, T is the string tension in Newtons, g is gravitational acceleration (9.8 m/s²), and a is the magnitude of acceleration (m/s²). Both equations use Newton’s second law: net force = mass × acceleration.

Step 3 — Solve the System of Equations

Add the two equations to eliminate T:

m2g − m1g = (m1 + m2)a

Solving for acceleration:

a = (m2 − m1)g / (m1 + m2)

Substitute back to find tension:

T = m1(g + a) = 2m1m2g / (m1 + m2)

Notice: if m1 = m2, then a = 0 and T = m1g. The system stays in equilibrium — which makes perfect physical sense.

Worked Example

Let m1 = 3.0 kg and m2 = 5.0 kg.

Quantity Calculation Result
Acceleration a (5.0 − 3.0) × 9.8 / (3.0 + 5.0) 2.45 m/s²
Tension T 2 × 3.0 × 5.0 × 9.8 / (3.0 + 5.0) 36.75 N

As a PhD in Physics, I can tell you that the most powerful check here is units: (kg·m/s²) = N throughout. Also verify that T lies between m1g (29.4 N) and m2g (49.0 N) — it always should, since the tension must partially support each mass while still allowing acceleration. This cross-check alone catches most arithmetic errors. For deeper practice with connected-system problems, the Classical (Newtonian) Mechanics resource at My Physics Buddy is excellent. You can also review Newton’s laws at the foundational level via Khan Academy’s AP Physics Atwood machine guide.

Common Mistakes with Atwood Machine Problems

Mistake: Assigning opposite tension values to the two masses, writing T1 for m1 and T2 for m2.
Fix: For a massless, frictionless pulley with an inextensible string, there is only one tension T throughout the entire string. Use the same symbol T in both equations.

Mistake: Using the same sign for both masses without setting a consistent positive direction, leading to a = 0 or a negative nonsensical result.
Fix: Explicitly state your sign convention before writing equations. Positive for m1 is upward; positive for m2 is downward. This makes acceleration appear positive in both equations.

Mistake: Forgetting to verify the tension answer is physically reasonable — e.g., accepting T greater than m2g.
Fix: Always check that m1g < T < m2g. If this inequality fails, an algebraic or sign error exists somewhere in your solution.

Exam Relevance: Atwood machine problems appear in AP Physics 1, AP Physics C: Mechanics, IB Physics HL/SL, and A/AS Level Physics (9702). They test Newton’s second law, tension in connected systems, and kinematic constraint reasoning.

💡 Pro Tip from Dr Shivani G: Treat the whole Atwood system as one object of mass (m1 + m2) driven by net force (m2 − m1)g to find acceleration instantly, then use one individual equation just for tension.

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